This page shows how to construct a perpendicular to a line through an external point, using only a compass and straightedge or ruler. It works by creating a line segment on the given line, then bisecting it. The bisector will be a right angles to the given line. (See proof below).
The above animation is available as a printable step-by-step instruction sheet, which can be used for making handouts or when a computer is not available.
The image below is the final drawing above with the red lines added.
| Argument | Reason | |
|---|---|---|
| 1 | Segment RP is congruent to RQ | They were both drawn with the same compass width |
| 2 | Segment SQ is congruent SP | They were both drawn with the same compass width |
| 3 | Triangle RQS is congruent to triangle RPS | Three sides congruent (sss), RS is common to both. |
| 4 | Angle JRQ is congruent to JRP | CPCTC. Corresponding parts of congruent triangles are congruent. |
| 5 | Triangle RJQ is congruent to triangle RJP | Two sides and included angle congruent (SAS), RJ is common to both. |
| 6 | Angle RJP and RJQ are congruent | CPCTC. Corresponding parts of congruent triangles are congruent. |
| 7 | Angle RJP and RJQ are 90° | They are congruent and supplementary (add to 180°). |