Vertical line (Coordinate Geometry)
Drag the points A or B and note the line is vertical when they both have the same
A vertical line is one the goes straight up and down,
parallel to the y-axis of the coordinate plane. All
points on the line will have the same x-coordinate.
In the figure above, drag either point and note that the line is vertical when they both have the same x-coordinate.
A vertical line has no
slope. Or put another way, for a vertical line the slope is undefined. As you
drag the points above, notice that the slope indicator goes away when the line is exactly vertical.
The equation of a vertical line is
Notice that the equation is independent of y. Any point on the vertical line satisfies the equation.
x = a
|| is the coordinate of any point on the line
||is where the line crosses the x-axis (x intercept).
Determine if the line shown in Fig 1 is vertical and write its equation.
Fig 1. Is the line vertical?
The points A and B on the line are at (-15,3) and (-15,20).
The first coordinate in each pair is the x-coordinate which are -15, and -15.
Since they are equal, the line is vertical.
Since the line crosses the x-axis at -15, the equation of the line is
x = -15;
which can be read as "for all values of y, x is -15".
Things to try
In the figure at the top of the page, drag the points around and note how points on vertical lines can have any y-coordinate,
but the x-coordinates are the same.
Click "hide details". Adjust the points to create a new vertical line. Write down the equation of the line
and then click "show details" to verify your answer.
In the interest of clarity in the applet above, the coordinates are rounded off to integers and the lengths rounded to one decimal place.
This can cause calculatioons to be slightly off.
For more see
While you are here..
... I have a small favor to ask. Over the years we have used advertising to support the site so it can remain free for everyone.
However, advertising revenue is falling and I have always hated the ads. So, would you go to Patreon and become a patron of the site?
When we reach the goal I will remove all advertising from the site.
It only takes a minute and any amount would be greatly appreciated.
Thank you for considering it! – John Page
Become a patron of the site at patreon.com/mathopenref
Other linear equation topics
Linear Function Explorer
(C) 2011 Copyright Math Open Reference. All rights reserved