Constructing a 45° angle
Geometry construction using a compass and straightedge
Step-by-step Instructions Printer friendly version
After doing this Your work should look like this
1.  Draw a line segment which will become one side of the angle. (Skip this step if you are given this line.) The exact length is not important. Label it PQ. P will be the angle's vertex. Geometry construction with compass and straightedge or ruler or ruler
In the next 3 steps we create the perpendicular bisector of PQ.
See Constructing a perpendicular bisector of a line segment
2.  Set the compass width to just over half the length of the line segment PQ. Geometry construction with compass and straightedge or ruler or ruler
3.  With the compass point on P then Q, draw two arcs that cross above and below the line. Geometry construction with compass and straightedge or ruler or ruler
4.  Draw a line between the two arc intersections. This is at right angles to PQ and bisects it (divides it in exactly half). Geometry construction with compass and straightedge or ruler or ruler
 
5.  With the compass point on the intersection of PQ and the perpendicular just drawn, set the compass width to P Geometry construction with compass and straightedge or ruler or ruler
6.  Draw an arc across the perpendicular, creating the point C Geometry construction with compass and straightedge or ruler or ruler
7.  Draw a line from P through C, and on a little more. The end of this line is point R Geometry construction with compass and straightedge or ruler or ruler
8.  Done. The angle QPR has a measure of 45° Geometry construction with compass and straightedge or ruler or ruler

Proof

This construction works by creating an isosceles right triangle, which is a 45-45-90 triangle. The image below is the final drawing above with the red items added.

  Argument Reason
1 Line segment AB is perpendicular to PQ. Constructed that way. See Constructing the perpendicular bisector of a line.
2 Triangle APC is a right triangle Angle ACP is 90° (from step 1)
3 Line segments CP,CA are congruent Drawn with same compass width
4 Triangle ∆APC is isosceles. CP = AC
5 Angle APC has a measure of 45°. In isosceles triangle APC, base angles CPA and CAP are congruent. (See Isosceles Triangles). The third angle ACP is 90° and the interior angles of a triangle always add to 180. So both base angles CPA and CAP are 45°.

  - Q.E.D
Try it yourself
Click here for a printable worksheet containing two 45° angle exercises. When you get to the page, use the browser print command to print as many as you wish. The printed output is not copyright.

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